Type Challenges Judge

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Promise.all

提出詳細

declare function PromiseAll<T extends readonly any[]>(
  values: T
): Promise<{
  [K in keyof T]: T[K] extends Promise<infer R> ? R : T[K]
}>;
提出日時2025-02-17 14:11:51
問題Promise.all
ユーザーbalckowl
ステータスWrong Answer
テストケース
import type { Equal, Expect } from '@type-challenges/utils'

const promiseAllTest1 = PromiseAll([1, 2, 3] as const)
const promiseAllTest2 = PromiseAll([1, 2, Promise.resolve(3)] as const)
const promiseAllTest3 = PromiseAll([1, 2, Promise.resolve(3)])

type cases = [
  Expect<Equal<typeof promiseAllTest1, Promise<[1, 2, 3]>>>,
  Expect<Equal<typeof promiseAllTest2, Promise<[1, 2, number]>>>,
  Expect<Equal<typeof promiseAllTest3, Promise<[number, number, number]>>>,
]